Hi all,
just request anyone to help with a solution or with ideas on how to subnet one block IP address into 3 only subnets all of which support a total of about 500 hosts. Let's take for example a class B IP address like 172.16.0.1
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Question
0
Votes
3 subnets, one block IP address, 500 hosts
7th Oct 2008
Answers (5)
0
Votes
VLSM is the answer
http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a00800a67f5.shtml
Other guides are abound on the web.
Other guides are abound on the web.
7th Oct 2008
0
Votes
Here's your data
Given address 172.16.0.1
Subnet zero address= 172.16.0.0
Subnets needed=3
3>2 (2^1=2)
34 (2^2=4)
Therefore, two bits, working to the right=192
Or, 256-192 = 32
Either way, Block size is =32
172.16.0.0 /26 CIDR for 8 subnets, 30 usable hosts per subnet.
172.16.0.0 .1 - .30 .31
.32 .33 - .62 .63
.64 .65 - .94 .95
.96 .97 - .126 .127
.128 .129 - .158 .159
.160 .161 - .190 .191
.192 .193 - .222 .223
.224 .225 - .254 .255
Subnet zero address= 172.16.0.0
Subnets needed=3
3>2 (2^1=2)
34 (2^2=4)
Therefore, two bits, working to the right=192
Or, 256-192 = 32
Either way, Block size is =32
172.16.0.0 /26 CIDR for 8 subnets, 30 usable hosts per subnet.
172.16.0.0 .1 - .30 .31
.32 .33 - .62 .63
.64 .65 - .94 .95
.96 .97 - .126 .127
.128 .129 - .158 .159
.160 .161 - .190 .191
.192 .193 - .222 .223
.224 .225 - .254 .255
1st May 2010
0
Votes
Oops! Correction-
Given address 172.16.0.1
Subnet zero address= 172.16.0.0
Subnets needed=3
>=500 hosts
Block size is =512 -2 = 510 Hosts
172.16.0.0 /23 510 usable hosts per subnet.
172.16.0.0/23 .1 - 1.254 1.255
2.0/22 2.1 - 3.254 3.255
4.0/21 4.1 - 5.254 5.255
Subnet zero address= 172.16.0.0
Subnets needed=3
>=500 hosts
Block size is =512 -2 = 510 Hosts
172.16.0.0 /23 510 usable hosts per subnet.
172.16.0.0/23 .1 - 1.254 1.255
2.0/22 2.1 - 3.254 3.255
4.0/21 4.1 - 5.254 5.255
1st May 2010
0
Votes
hi
given address 172.16.0.0/22
500hosts
60hosts
30hosts
10hosts
WAN 1:hosts
WAN 2:hosts
pls answer =(
500hosts
60hosts
30hosts
10hosts
WAN 1:hosts
WAN 2:hosts
pls answer =(
18th Jun
Replies
pls help pls pls pls
kyleadrian
18th Jun
Hi this is your answer
500 hosts: 172.16.0.0/23 range 172.168.0.0 - 172.16.1.255, max hosts 510.
60 hosts: 172.16.2.0/26 range 172.16.2.0 - 172.16.2.63, max hosts 63.
30 hosts: 172.16.2.64/27 range 172.16.2.64 - 172.16.2.95.
10 hosts: 172.16.2.96/28 range 172.16.2.96 - 172.16.2.111, max hosts 14.
2 hosts: 172.16.2.112/30 range 172.16.2.112 - 172.16.2.115.
1 host: 172.16.2.116/30 range 172.16.1.116 - 172.16.2.119
Hope that helps
Martin
500 hosts: 172.16.0.0/23 range 172.168.0.0 - 172.16.1.255, max hosts 510.
60 hosts: 172.16.2.0/26 range 172.16.2.0 - 172.16.2.63, max hosts 63.
30 hosts: 172.16.2.64/27 range 172.16.2.64 - 172.16.2.95.
10 hosts: 172.16.2.96/28 range 172.16.2.96 - 172.16.2.111, max hosts 14.
2 hosts: 172.16.2.112/30 range 172.16.2.112 - 172.16.2.115.
1 host: 172.16.2.116/30 range 172.16.1.116 - 172.16.2.119
Hope that helps
Martin
MartinG13
19th Jun
0
Votes
Please Help!
Need an addressing scheme to support.
500 hosts
300 hosts
150 hosts
150 hosts
50 hosts
10 hosts
2 Hosts
500 hosts
300 hosts
150 hosts
150 hosts
50 hosts
10 hosts
2 Hosts
11th Feb

































