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3 subnets, one block IP address, 500 hosts

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3 subnets, one block IP address, 500 hosts

dweddi
Hi all,
just request anyone to help with a solution or with ideas on how to subnet one block IP address into 3 only subnets all of which support a total of about 500 hosts. Let's take for example a class B IP address like 172.16.0.1
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    renodogs

    Given address 172.16.0.1
    Subnet zero address= 172.16.0.0
    Subnets needed=3
    3>2 (2^1=2)
    3<4 (2^2=4)
    Therefore, two bits, working to the right=192

    Or, 256-192 = 32

    Either way, Block size is =32

    172.16.0.0 /26 CIDR for 8 subnets, 30 usable hosts per subnet.

    172.16.0.0 .1 - .30 .31
    .32 .33 - .62 .63
    .64 .65 - .94 .95
    .96 .97 - .126 .127
    .128 .129 - .158 .159
    .160 .161 - .190 .191
    .192 .193 - .222 .223
    .224 .225 - .254 .255

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    renodogs

    Given address 172.16.0.1
    Subnet zero address= 172.16.0.0
    Subnets needed=3
    >=500 hosts
    Block size is =512 -2 = 510 Hosts

    172.16.0.0 /23 510 usable hosts per subnet.

    172.16.0.0/23 .1 - 1.254 1.255
    2.0/22 2.1 - 3.254 3.255
    4.0/21 4.1 - 5.254 5.255

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    hi

    kyleadrian

    given address 172.16.0.0/22
    500hosts
    60hosts
    30hosts
    10hosts
    WAN 1:hosts
    WAN 2:hosts

    pls answer =(

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    kyleadrian

    pls help pls pls pls

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    MartinG13

    Hi this is your answer
    500 hosts: 172.16.0.0/23 range 172.168.0.0 - 172.16.1.255, max hosts 510.
    60 hosts: 172.16.2.0/26 range 172.16.2.0 - 172.16.2.63, max hosts 63.
    30 hosts: 172.16.2.64/27 range 172.16.2.64 - 172.16.2.95.
    10 hosts: 172.16.2.96/28 range 172.16.2.96 - 172.16.2.111, max hosts 14.
    2 hosts: 172.16.2.112/30 range 172.16.2.112 - 172.16.2.115.
    1 host: 172.16.2.116/30 range 172.16.1.116 - 172.16.2.119

    Hope that helps

    Martin

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    Sphinx23

    Need an addressing scheme to support.
    500 hosts
    300 hosts
    150 hosts
    150 hosts
    50 hosts
    10 hosts
    2 Hosts

  • +
    0 Votes
    renodogs

    Given address 172.16.0.1
    Subnet zero address= 172.16.0.0
    Subnets needed=3
    3>2 (2^1=2)
    3<4 (2^2=4)
    Therefore, two bits, working to the right=192

    Or, 256-192 = 32

    Either way, Block size is =32

    172.16.0.0 /26 CIDR for 8 subnets, 30 usable hosts per subnet.

    172.16.0.0 .1 - .30 .31
    .32 .33 - .62 .63
    .64 .65 - .94 .95
    .96 .97 - .126 .127
    .128 .129 - .158 .159
    .160 .161 - .190 .191
    .192 .193 - .222 .223
    .224 .225 - .254 .255

    +
    0 Votes
    renodogs

    Given address 172.16.0.1
    Subnet zero address= 172.16.0.0
    Subnets needed=3
    >=500 hosts
    Block size is =512 -2 = 510 Hosts

    172.16.0.0 /23 510 usable hosts per subnet.

    172.16.0.0/23 .1 - 1.254 1.255
    2.0/22 2.1 - 3.254 3.255
    4.0/21 4.1 - 5.254 5.255

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    0 Votes

    hi

    kyleadrian

    given address 172.16.0.0/22
    500hosts
    60hosts
    30hosts
    10hosts
    WAN 1:hosts
    WAN 2:hosts

    pls answer =(

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    0 Votes
    kyleadrian

    pls help pls pls pls

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    0 Votes
    MartinG13

    Hi this is your answer
    500 hosts: 172.16.0.0/23 range 172.168.0.0 - 172.16.1.255, max hosts 510.
    60 hosts: 172.16.2.0/26 range 172.16.2.0 - 172.16.2.63, max hosts 63.
    30 hosts: 172.16.2.64/27 range 172.16.2.64 - 172.16.2.95.
    10 hosts: 172.16.2.96/28 range 172.16.2.96 - 172.16.2.111, max hosts 14.
    2 hosts: 172.16.2.112/30 range 172.16.2.112 - 172.16.2.115.
    1 host: 172.16.2.116/30 range 172.16.1.116 - 172.16.2.119

    Hope that helps

    Martin

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    0 Votes
    Sphinx23

    Need an addressing scheme to support.
    500 hosts
    300 hosts
    150 hosts
    150 hosts
    50 hosts
    10 hosts
    2 Hosts