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ip address range

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hm.

Rob Kuhn

isn't the power just doubled and tripled for the respected class?

2^14 for class B and 2^21 for class C. That at least gives us the number of possible network IDs for each of the respected classes.

Since I suspect that PurpleSkys is correct, can you, Aavarice, figure out what the number of host IDs per network ID is for each of the respected classes are?

Hint:

Class A: Total number of network ID: 8, Host ID: 24
Answer: 2^(what power) - 2

Class B: Total number of network ID: 16, Host ID: 16
Answer: 2^(what power) - 2

Class C: Total number of network ID: 24, Host ID 8
Answer: 2^(what power) - 2

Should be fairly simple. :)