comparing a string
Hi,
i have string str ="IP>10.2.2.1 and IP<10.2.2.10,10.2.2.31";
i have one more string str1 ="10.2.2.5";
i need to search whether str1 exists in str.
need a sample program for searching .
Thanks in Advance
Junk
Hi,
i have string str ="IP>10.2.2.1 and IP<10.2.2.10,10.2.2.31";
i have one more string str1 ="10.2.2.5";
i need to search whether str1 exists in str.
need a sample program for searching .
Thanks in Advance
by 2rajesh.b Accepted solution
by Former member Accepted solution
Grep is the "best" tool to look for a string in a text file.
If you are using Linux/Unix, use grep. See http://www.gnu.org/software/grep/ for more info.
If you are using Windows, see http://gnuwin32.sourceforge.net/packages/grep.htm for more info.
Afraid of the command line (grep is a command line tool), import your text file to MS Excel, Word, etc. and use CTRL+F and search for the string that way.
by robo_dev Accepted solution
Check all that apply:
[ ] DOS Batch
[ ] ASP
[ ] C++
[ ] Java
[ ] Visual Basic
[ ] Fortran
[ ] ADA
[ ] SPSS-X
[ ] COBOL
[ ] Morse Code
[ ] Intel Assembler
by cmiller5400 Accepted solution
by 2rajesh.b Accepted solution
by wancona Accepted solution
This is a vb script. Do you mean something like this?
On Error Resume Next
intStartingAddress = 1
intEndingAddress = 31
strSubnet = "10.2.2."
strAddress = 5
For i = intStartingAddress to intEndingAddress
strComputer = strSubnet & i
if i = strAddress AND i < intEndingAddress then
Wscript.Echo strComputer
end if
Next
by 2rajesh.b Accepted solution
Hi
i have a string like 'X>10.10.1.0 and x<10.10.1.10'
how can i split this into intStartingAddress = 1
intEndingAddress = 10
i need to split and check in that range whether my IP is in that range.
i am completely new to VB
by wancona Accepted solution
The first three octets (10.10.1.) goes into the strSubnet.
The intStartingAddress goes to 0 because that is the lesser of the two numbers in the fourth octet
The intEndingAddress goes to 10 or whatever the higher number of the last octet is.
strAddress is the number (x) in the last octet of the address you are searching for.
This small script only works on checking the last octet, but with some modifications, can work other ways.
by 2rajesh.b Accepted solution
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