Linux
e.g. wc -l filename
gives: 2000 filename
This gives the # of lines and also shows the filename.
I want to extract the # of lines only (2000) and not show the filename. I want to try to do this in one line and not have temporary lines.
Thanks
by cactus pete
You could pipe it to awk and remove just the one space delimited column you wanted...
wc -l filename |awk $1
That might do it, though I don't have a nix box at my fingertips right now
by cactus pete
Actually, that would be wrong [syntax is different], and there's something perhaps better:
cat filename | wc -l
That should do it.
by gary_w
Take it a step further and get rid of leading blanks or tabs too by assigning the result to an integer variable. Using the korn shell, which supports this:
#!/usr/bin/ksh
integer linecount=`cat filename|wc -l`
Use $linecount to refer to the linecount in your script as:
echo $linecount
Gary
by rgooding
I already have a file with one line. The contents of the line looks like: 4000 filename.txt.
What I need is to get the "4000" from the line.
Hope this explains it further...Thanks agin
by gary_w
Ok, here ya go:
# Cut field 1 where the delimiter is a space.
integer linecount=`cat filename|cut -f1 -d' '`
echo $linecount
Mote that there is a space between the single quotes.
Gary
by rgooding
GREAT!!!! That is exactly what I need. Thanks a lot.
Richard
by rgooding
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