i have collect a sample code of accessing yahoo address book from this site. The full code given below,
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Create URL
$url = “https://login.yahoo.com/config/login?”;
$query_string = “.tries=2&.src=ym&.md5=&.hash=&.js=&.last=&promo=&.intl=us&.bypass=&.partner=&.u=4eo6isd23l8r3&.v=0&.challenge=gsMsEcoZP7km3N3NeI4mXkGB7zMV&.yplus=&.emailCode=&pkg=&stepid=&.ev=&hasMsgr=1&.chkP=Y&.done=http%3A%2F%2Fmail.yahoo.com&login=$email_id&passwd=$password”;
$url_login = $url . $query_string;
##—> End Create URL
##—> Execute Curl For Login
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url_login);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY);
curl_setopt ($ch, CURLOPT_COOKIEJAR, ‘cookie.txt’);
curl_setopt($ch, CURLOPT_HEADER , 1);
ob_start();
$response = curl_exec ($ch);
ob_end_clean();
curl_close ($ch);
unset($ch);
##—> End Execute Curl For Login
##—> Call Address Book Page Through Curl
$url_addressbook = “http://address.yahoo.com/yab/us”;
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_COOKIEFILE, “cookie.txt”);
curl_setopt($ch, CURLOPT_HEADER , 1);
curl_setopt($ch, CURLOPT_URL, $url_addressbook);
$result = curl_exec ($ch);
curl_close ($ch);
unset($ch);
##—> End Call Address Book Page Through Curl
##—> Manuplate String
$result = preg_replace(“([\r\n\t])”, ” “, $result);
$result = strip_tags($result);
$arr_result = explode(” “, $result);
$arr_filter = array();
for($i=0; $i
{
if(!in_array($arr_result[$i], $arr_filter, TRUE))
$arr_filter[] = $arr_result[$i];
}
}
##—> End Manuplate String
##—> Return Result Array
return $arr_filter;
##—> End Return Result Array
}
?>
“;
}
?>
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But the problem is that, when i run it, its display fatal error(below) at line no 19,
“Fatal error: Call to undefined function: curl_init() in c:\apache\htdocs\myaddbook.php on line 19”
the line 19 contain the following code,
“$ch = curl_init();”
just tell me that does this error means, how shuould i correct this.
——————————- Rashed