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RAID config Question

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6 replies

by lupster

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MY server is configured with the following disks:

Disk 0 contains two partitions (C: and D:). The C:
partition contains the operating system files and is
also the active partition. It is a 6 GB partition
of which 4 GB is currently in use. The D: partition
is a 2 GB partition with 1 GB currently in use.
There is 12 GB of unpartitioned free space available
on Disk 0.

Disk 1 does not contain any partitions. The capacity
of the disk is 20 GB.

Disk 2 does not contain any partitions. The capacity
is 12 GB.

All of the disks are dynamic disks. I would like to create a RAID-5 volume on the disks to achieve the maximum amount of available disk space to store data to. When I am finished how much useable space will
I have on the RAID-5 volume?

6 replies

by brian.biby

Raid 5 that I am familiar with requires at least three different physical disk drives. The final capacity will be (drives-1) * (size of smallest drive). For example, if there are three physical disks HD0 = 20G, HD1 = 12G, HD2 = 20G, then the raid volume resulting from these drives would have a capacity of 24G (quite a waste if you dont have drives approximately the same size!)

If you have a method to create a virtual Raid 5 Array based on volumes, I would expect the same logic would hold true as far as sizing. In your case it would make good sense to me to eliminate the "D:" partition, resize the "C:" partition to 8G (or a value that is acceptable to yoru OS for the system volume), create another 8G partition on HD1 as a Mirror of C,then use the remaining 12G's of HD0, HD1, & HD2 to create a virtual 24G Raid 5 partition.

All things considered, you might want to get a third 20G drive, and use 3-20G to make a 40G array and use the 12G as yoru system volume...

Good Luck!

by lupster

Thanks for your assisstance. Thats was what I was my conclusion. Just needed another head. to jog the memory.

by lupster

I am sorry. I was trying to give the points to Brian btu it took it as rejected.

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