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Remote Access

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We used to use pcAnywhere for remote managment.
We have changed the network so that the router is now using NAT for the internal network.
Obviously pcAnywhere can not get through anymore.
Looking for suggestions about using PPTP or VPN's or anything else that might work.
This is an NT network running primarily TCP/IP.
Will supply more info if requested.
Thanks......

9 replies

by jcox303

You could use Netmeeting's remote desktop feature. Works very well through firewalls, vpn and ras/dun. Are your clients static or dynamic?

by allan

does not answer the question about getting through the NAT on the router.

by norm.morrison

We have been using PCanywhere, NetMeeting and thin client sessions for about a year now for remote management.
All run within VPN sessions.
Of the three, if I had to pick only one, I'd pick a thin client session (especially if you have only a dialup connection). PC anywhere would run a close second. Net Meeting works well for connecting to workstations.

by allan

does not answer the question about getting through the NAT on the router.

by dao251

1) I believe PCanywhere can work over NAT. There is an article explaining that in their KB on www.symantec.com

2) only router-based VPN (PPTP or whatever) will immediately help in your case. Using any NT-based VPN you will face the same problem: "how to run my VPN through NAT-enabled router?"

Check you router IOS doc for VPN features.

by shmaltz

I have a network with the exact same setup.
we use a linux machine as a gateway/firewall and i just added a pptp server running Microsoft NT 4.0 sp6 and ras and the pptp protocol, I added the pptp server on the same level of the firewall which means that i have now 2 gateways to the internet and for security reasons I enabled PPTP filtering (and I think you should also do that) which disables the server from acting as a router/gateway to the internet the nic connected to the internet is assigned a public IP address and the one connected to the lan is assigned a private IP address and it just works fine.

by allan

Thanks, I'm going to try this.(but a little differently)
It seems to be the right approach.

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