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The trick is: the sum(Question_Points) = 150. For example, lets say Question_Points of the 1st row is 10, Question_Points of the 2nd row is 20, of the 3rd row is 15, and randomly so on. So, the sum of the selection need to be 150.

Greetings

So are you trying to select question text that has a sum of 150?
I hope these are in two different tables then.

Im a it rusty, but I think its something like

Select Question_Text, sum(Question_Points) From Questions Group by Question_Text

That should give you the total points for each question. I cannot remember how to narrow it down further.

I'll give you detailed example. Lets say the table is like this:
Id Question_Text Question_Points
1 Question1 5
2 Question2 5
3 Question3 10
4 Question4 5
5 Question5 5
Can we make elegant selection where sum(Question_Points) = 20, and the result set would be like this:
1 Question1 5
2 Question2 5
3 Question3 10
[5+5+10=20] , Or the result set would be like this:
3 Question3 10
4 Question4 5
5 Question5 5
[10+5+5=20] The sum is again 20, or the result set would be like this:
1 Question1 5
2 Question2 5
4 Question4 5
5 Question5 5
The sum is again 20. I'll emphasize again that the result selection should be randomly chosen. Hope better explained n 10x 4 ur attention.