5 replies
by ideafixer
Open the form in design view. On the left of the horizantal ruler in design view, a small grey box is located on the form.
Right click on this box and select properties. From the form properties, choose the event tabe. Click in the "On Open"event then click the three little dots next to this text box. A options screen will launch. Choose "Code Builder"
When in code builder paste this:
DoCmd.GoToRecord , , acNewRec
into the window. Paste it just above the "End Sub" line and under the "Private Sub Form_Load()". Basically paste it were the code builder first puts you when the screen is launched.
The above code will have the form go to a new record when the form is launched. Good Luck!
by dakota99
by georgevlob
Creat an Event Procedure for the event On Load and instert the following:
DoCmd.RunCommand acCmdRecordsGoToNew
This makes the form go to a new record after it has loaded all the data.
by dakota99
by dakota99
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