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Passing arguments in Unix Shell Script

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In a shell script, I want to be able to “ftp” to a machine and pass the username, password, put command, etc. but whenenver I run the script, it sits there waiting for me to enter the info. I predefined them in the script, but I don’t know how to pass them to the ftp command to get them to execute.

Thanks

Paul

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Passing arguments in Unix Shell Script

In reply to Passing arguments in Unix Shell Script

Try this in your script

ftp computer << EOF user username passwd cd /to/a/directory put files bye EOF

Passing arguments in Unix Shell Script

In reply to Passing arguments in Unix Shell Script

Sorry, this didn’t work! I ended up writing the ftp commands to a file as follows

ftp hostname < file.txt file.txt contains all I needed Thanks for the repsonse anyway

Passing arguments in Unix Shell Script

In reply to Passing arguments in Unix Shell Script

Paul,
Basically, you need username, password, and the put command. The username and password should be written to the users .netrc file. It should look like this:
default
login whateverusername
password whateverpassword
I think permissions haveto be set to r——–. (chmod 400)
Then, all that is left is the put command. Write out the put command to a file and cat the file piping throu the ftp command.
like this:
echo “put filename” > dummyfile
cat dummyfile | ftp
I think this shouldat least get you started.
John

Passing arguments in Unix Shell Script

In reply to Passing arguments in Unix Shell Script

See comment on Answer 1 above

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