# Networks

## General discussion

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### subnetting

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how many host and how many subnets will you have with an address of 172.16.13.0/11?

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### subnetting

by In reply to subnetting

Wait a second. 172.16.13.0 is in the Class B range of addresses (172-1** is Class B). So, when you subnet Class B addresses, you take bits from the 3rd octet in the subnet mask.
So, 172.16.13.0/11 would only have 3 bits ON in the 2nd octet, insteadof some bits in in the 3rd octet.

11111111.11100000.00000000.00000000 is 255.224.0.0 which is /11

So, the whole point of this is, I don't think you can subnet the network you have listed in the way you have listed.

Now, I can be wrong aboutthis. Subnetting is not my strong suit.

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### subnetting

by In reply to subnetting

There's an easy way to figure out how many hosts you can get from one particular subnet mask. Open your calculator in windows and make sure you that you are viewing scientific mode. Convert your subnet mask into binary. To figure out the number ofhost's, count the number of zero's in the subnetmask. In this case it's 21. On your calculator, hit (2 x^y 21)-2. Your answer is 2,097,150. That is the maximum number of host ip addresses. To get the number of networks, it's a little more detailed. I will tell you that max number of networks is 6.

By the way, the previous answer given is correct. If you are using a subnet mask of 255.224.0.0, then you cannot have a network ID of 172.16.x.x. Your network ranges will be:

172.32.0.1-172.63.255.254
172.64.0.1- 172.95.255.254
172.96.0.1- 172.128.255.254
And so on and so on.

I hope this helps.

-Norm

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### subnetting

by In reply to subnetting

There is a bunch of subnet calculators available. My personal favourite is available for free from 3com. Link:
ftp://ftp.3com.com/pub/utilbin/win32/3CIPCalc.zip
Description:
A freeware IP subnet calculator for Windows 95/98/NT
Size:
819200

HTH
/Tom

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