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subnetting

By azizhakim ·
Working on home project about subnetting & one area is a little cloudy.Emulating a two domain enviroment.creared two way trust relationship successfully on nt 4.0 platform.Server1 is gateway to server2 domain.Arbitrarily created two subnets in
192.168.64.x range.Subnetmask of 255.255.255.192 which allows me 2 subnets with 62 hosts.Subnet 1 with ip range 192.168.64.1-63, Subnet 2 with ip range 192.168.64.65-128.The area of dilemma is the delta or change part.My question is will both subnets be in 192.168.64.xx range or one in 192.168.64.(1-63) & the other in 192.168.128.(65-127).I certainly hope i made my question clear enough to warrant a reply.In essence the delta part is the confusion. THANX FOR ANY INPUT-AZIZ

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by nohdowt In reply to subnetting

Since you mask is 255.255.255.192, your subnets will be 192.168.64.1-63 and 192.168.64.64-127 because your subnet mask is filtering only in the last octet.
The third octet definitely doesn't change.

Hope this helps...

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by azizhakim In reply to subnetting

Thanx.Very helpful.that is exaclty how i thought it out.NOW THE UNCERTAINTY HAS CLEARED.Once again--thanx-aziz

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by tony.colgrove In reply to subnetting

When useing 192.168.64.xx and a subnet mask of 255.255.255.192, your two valid networks are 192.168.64.64 (host id's 65-126. 64 is the network ID, and 127 is the network broadcast ID) the other network is 192.168.64.128 (host id's 129-190. 128 is the network ID and 1** is the network broadcast ID) Address 0-63, and 192-255 are lost because of subnetting a "C class".

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by azizhakim In reply to subnetting

thanx,input has cleared it up,once again thanx--aziz

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by -J- In reply to subnetting

The actual subnet for the 192.168.64.x with the subnet of 255.255.255.192 should look like this:

Subnet 1 (UNUSEABLE because network address would be all zeros)
.0 = network address
.1-.62 = Host address
.63 = Broadcast address

Subnet 2 (USEABLE)
.64 = Network Address
.65-.126 = Host Address
.127 = Broadcast Address

Subnet 3 (USEABLE)
.128 = Network Address
.129-.190 = Host Address
.1** = Broadcast Address

Subnet 4 (UNUSEABLE becasue Network address would be all ones)
.192= Network Address
.193-.254 = Host Address
.255 = Broadcast Address

Server 1 should be in Subnet 2 and Server 2 should be in Subnet 3. Not sure if this answers your question or not. Hope this helps.

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subnetting

by azizhakim In reply to subnetting

Thanx for input,got it now
---thanx once again--aziz

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by azizhakim In reply to subnetting

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