Windows·65,577 discussions

subnetting

Locked

Working on home project about subnetting & one area is a little cloudy.Emulating a two domain enviroment.creared two way trust relationship successfully on nt 4.0 platform.Server1 is gateway to server2 domain.Arbitrarily created two subnets in
192.168.64.x range.Subnetmask of 255.255.255.192 which allows me 2 subnets with 62 hosts.Subnet 1 with ip range 192.168.64.1-63, Subnet 2 with ip range 192.168.64.65-128.The area of dilemma is the delta or change part.My question is will both subnets be in 192.168.64.xx range or one in 192.168.64.(1-63) & the other in 192.168.128.(65-127).I certainly hope i made my question clear enough to warrant a reply.In essence the delta part is the confusion. THANX FOR ANY INPUT-AZIZ

Topic

subnetting

In reply to subnetting

Since you mask is 255.255.255.192, your subnets will be 192.168.64.1-63 and 192.168.64.64-127 because your subnet mask is filtering only in the last octet.
The third octet definitely doesn’t change.

Hope this helps…

subnetting

In reply to subnetting

Thanx.Very helpful.that is exaclty how i thought it out.NOW THE UNCERTAINTY HAS CLEARED.Once again–thanx-aziz

subnetting

In reply to subnetting

When useing 192.168.64.xx and a subnet mask of 255.255.255.192, your two valid networks are 192.168.64.64 (host id’s 65-126. 64 is the network ID, and 127 is the network broadcast ID) the other network is 192.168.64.128 (host id’s 129-190. 128 is the network ID and 191 is the network broadcast ID) Address 0-63, and 192-255 are lost because of subnetting a “C class”.

subnetting

In reply to subnetting

thanx,input has cleared it up,once again thanx–aziz

subnetting

In reply to subnetting

The actual subnet for the 192.168.64.x with the subnet of 255.255.255.192 should look like this:

Subnet 1 (UNUSEABLE because network address would be all zeros)
.0 = network address
.1-.62 = Host address
.63 = Broadcast address

Subnet 2 (USEABLE)
.64 = Network Address
.65-.126 = Host Address
.127 = Broadcast Address

Subnet 3 (USEABLE)
.128 = Network Address
.129-.190 = Host Address
.191 = Broadcast Address

Subnet 4 (UNUSEABLE becasue Network address would be all ones)
.192= Network Address
.193-.254 = Host Address
.255 = Broadcast Address

Server 1 should be in Subnet 2 and Server 2 should be in Subnet 3. Not sure if this answers your question or not. Hope this helps.

subnetting

In reply to subnetting

Thanx for input,got it now
—thanx once again–aziz

subnetting

In reply to subnetting

This question was closed by the author

[Author]

Replies