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USB jumpdrive question

By jjs1984 ·
I just purchased a 1 gig USB lexar jumpdrive. It had security capabilities so i can partition the jumprdrive off into a secure, password protected area and a public area. When you plug the jumpdrive in it goes under Hard Disk Drives, instead of removeable media. Because it isn't removeable media i need admin priveleges to access it (which i don't have in a school environment). Any idea's for fixing that problem?

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possible idea?

by Senior Program Analyst In reply to USB jumpdrive question

Im not real familiar with the USB (that has the secure area) but,

Idea 1) Have someone who does have access to admin previlage to re-do the access levels on the drive

Idea 2) if you set up the secured area then from the same machine and same login ID you used to originally create the areas, access and modify the security levels - If you want to use on multiple PCs you may have to give temporary access to all users - then from the second machine (such as your home Pc) give access to yourself or a group on that machine. After which you should be able to reduce the access back by removing the All access.

If anyone has more info on this please put your two bits in - feel free to correct my ideas like I said...Im sort of guessing here but think it should work this way.

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possible idea?

by Senior Program Analyst In reply to USB jumpdrive question

Im not real familiar with the USB (that has the secure area) but,

Idea 1) Have someone who does have access to admin previlage to re-do the access levels on the drive

Idea 2) if you set up the secured area then from the same machine and same login ID you used to originally create the areas, access and modify the security levels - If you want to use on multiple PCs you may have to give temporary access to all users - then from the second machine (such as your home Pc) give access to yourself or a group on that machine. After which you should be able to reduce the access back by removing the All access.

If anyone has more info on this please put your two bits in - feel free to correct my ideas like I said...Im sort of guessing here but think it should work this way.

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